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If \(\underset{\sim}{A}\) = near 0.74 = \(\{ \frac{0}{0.730} + \frac{0.8}{0.735} + \frac{1}{0.740}\) \(+ \frac{0.6}{0.745} + \frac{0}{0.750} \}\)

and \(\underset{\sim}{B}\) = in 0.74 = \(\{ \frac{0}{0.730} + \frac{0.4}{0.735} + \frac{0.8}{0.740}\) \(+ \frac{1}{0.745} + \frac{0.6}{0.750} \}\)

then \(\overline{A \cup B}\) is :

  • A.\(\{ \frac{1}{0.730} + \frac{0.2}{0.735} + \frac{0}{0.740}\) \(+ \frac{0.4}{0.745} + \frac{1}{0.750} \}\)
  • B.\(\{ \frac{1}{0.730} + \frac{0.6}{0.735} + \frac{0.2}{0.740}\) \(+ \frac{0}{0.745} + \frac{0.4}{0.750} \}\)
  • C.\(\{ \frac{2}{0.730} + \frac{0.8}{0.735} + \frac{0.2}{0.740}\) \(+ \frac{0.4}{0.745} + \frac{0.6}{0.750} \}\)
  • D.\(\{ \frac{1}{0.730} + \frac{0.2}{0.735} + \frac{0}{0.740}\) \(+ \frac{0}{0.745} + \frac{0.4}{0.750} \}\)

Answer: D

The complement of the union is option D: grades 1, 0.2, 0, 0, 0.4 at 0.730, 0.735, 0.740, 0.745 and 0.750.

For fuzzy sets, the union takes the maximum grade at each point and the complement takes 1 minus the grade.

xABmax1 - max
0.7300001
0.7350.80.40.80.2
0.74010.810
0.7450.6110
0.75000.60.60.4

Option A has 0.4 and 1 in the last two places, the complement of A alone; option B uses the complement of the intersection in places; and option C has a grade of 2, which is impossible for a fuzzy set.

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