Machine-translated by Google. Questions are authored in English.
Top

Discussion

A 6 cm × 4 cm rectangular wave guide is filled with dielectric of refractive index 1.25. The range of frequencies over which single mode operation will occur is :

  • A.2.24 GHz \(\lt f \lt\) 3.33 GHz
  • B.2 GHz \(\lt f \lt\) 3 GHz
  • C.4.4 GHz \(\lt f \lt\) 70 GHz
  • D.4 GHz \(\lt f \lt\) 6 GHz

Answer: B

Single-mode operation occurs for 2 GHz \(\lt f \lt\) 3 GHz.

In a guide filled with a dielectric of index \(n\), waves travel at \(v = c/n = 2.4 \times 10^{8}\) m/s. The cut-off frequencies are \(f_{mn} = \frac{v}{2}\sqrt{(m/a)^{2} + (n/b)^{2}}\) with \(a = 6\) cm and \(b = 4\) cm:

\[ \begin{aligned} f_{10} &= \frac{2.4 \times 10^{8}}{2 \times 0.06} \\ &= 2\ \text{GHz} \\ f_{01} &= \frac{2.4 \times 10^{8}}{2 \times 0.04} \\ &= 3\ \text{GHz} \end{aligned} \]

Between these only TE10 propagates. The other ranges do not match these cut-offs; without the dielectric the window would be 2.5 to 3.75 GHz, which is not offered either.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.