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The oxidation numbers of carbon and hydrogen in methane are respectively

  • A.+4 and +1
  • B.+4 and 0
  • C.-4 and +1
  • D.-4 and -1
  • E.+4 and -1

Answer: C

The oxidation numbers are -4 and +1.

In CH4, hydrogen bonded to a non-metal has oxidation number +1. The molecule is neutral, so the oxidation numbers must add to zero:

\[ \begin{aligned} x + 4(+1) &= 0 \\ x &= -4 \end{aligned} \]

Carbon is more electronegative than hydrogen, which is why it carries the negative value. Any option giving carbon +4 or hydrogen 0 or -1 breaks this rule; hydrogen is -1 only in metal hydrides such as NaH.

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