Discussion
Using stock notation, match the oxidation number against metal in its compound.
| Compound | Oxidation Number of the metal |
|---|---|
| MnO | (a) IV |
| MnO2 | (b) II |
| Fe2O3 | (c) I |
| Tl2O | (d) III |
Answer: A
The matching is (i)-(b), (ii)-(a), (iii)-(d), (iv)-(c), taking the compounds in the order listed.
With oxygen at -2: MnO has Mn(II), so manganese(II) oxide (b); MnO2 has Mn(IV), manganese(IV) oxide (a); Fe2O3 has 2x = +6, so Fe(III), iron(III) oxide (d); Tl2O has 2x = +2, so Tl(I), thallium(I) oxide (c).
Stock notation writes this oxidation number in Roman numerals after the metal's name. The other options swap Fe2O3 and MnO2, or give Tl2O a higher state, which the formula does not allow.
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