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Chlorine has oxidation number +7 in

  • A.NaCl
  • B.\(\mathrm{SiCl_{4}}\)
  • C.HCl
  • D.\(\mathrm{HClO_{4}}\)
  • E.KCl

Answer: D

Chlorine is +7 in HClO4.

In perchloric acid, hydrogen is +1 and each of the four oxygens is -2: 1 + x + 4(-2) = 0, so x = +7, chlorine's highest oxidation state.

In NaCl, KCl, HCl and SiCl4 chlorine is bonded to a less electronegative element and has the oxidation number -1. In general chlorine's positive states appear only with oxygen or fluorine: +1 in HClO, +3 in HClO2, +5 in HClO3 and +7 in HClO4.

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