Discussion
Determine the C.O.P. of a refrigeration system if the work input is 80 kJ/kg and refrigeration effect produced is 120 kJ/kg of refrigerant flowing?
Answer: B
The COP is 1.5. The coefficient of performance of a refrigerator is the refrigeration effect divided by the work input: \[ COP = \frac{120}{80} = 1.5 \] The value 1.33 would result from dividing 80 by 60 and 2.0 and 3.0 do not follow from dividing 120 by 80, so only 1.5 is right.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development