Machine-translated by Google. Questions are authored in English.
Top

Discussion

Suppose the lifetimes of two systems, system 1 and system 2, follow exponential distributions with failure rates 2 and ½ respectively. Let the probability that system 'i' fails prior to its mean time to failure be denoted by pi, i = 1, 2. Which of the following is true ?

  • A.\(p_{1} \gt p_{2}\)
  • B.\(p_{1} = p_{2}\)
  • C.\(p_{1} \lt p_{2}\)
  • D.\(p_{1} \cdot p_{2} = 1\)

Answer: B

p1 = p2.

For an exponential lifetime with failure rate \(\lambda\), the mean time to failure is \(1/\lambda\), and

\[ \begin{aligned} P\left(T \lt \frac{1}{\lambda}\right) &= 1 - e^{-\lambda \cdot 1/\lambda} \\ &= 1 - e^{-1} \\ &\approx 0.632 \end{aligned} \]

whatever the rate. So both systems have the same probability, about 0.632, of failing before their own mean life; the rates 2 and ½ change the mean but not this probability. Their product is about 0.4, not 1.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.