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A system consists of 4 components, 3 of which form a parallel subsystem connected in series with the 4th component. The components work independently of each other. If the reliability of each component is 0.8, then the system reliability is :

  • A.0.8381
  • B.0.7132
  • C.0.4096
  • D.0.7936

Answer: D

The system reliability is 0.7936.

The parallel block of three components fails only if all three fail, and it is in series with the fourth component:

\[ \begin{aligned} R_{\text{parallel}} &= 1 - (0.2)^{3} = 0.992 \\ R &= 0.992 \times 0.8 = 0.7936 \end{aligned} \]

0.4096 is \(0.8^{4}\), all four components in series. The other values do not follow from this structure.

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