Discussion
A building of seismic weight 10 000 kN has a design horizontal seismic coefficient of 0.05. Its design base shear is
Answer: A
Correct answer: 500 kN
\[ V_B = A_h W = 0.05 \times 10\,000 = 500\ \text{kN.} \] The base shear is simply the seismic coefficient times the seismic weight, and it is then distributed up the height of the building in proportion to \( W_i h_i^2 \) in the static method. Note that the seismic weight is not the full gravity load - only part of the imposed load is included.
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