Discussion
A system has a period of 0.5 s and reads a spectral acceleration of 0.4 g. Its spectral displacement is closest to
Answer: B
Spectral displacement is the spectral acceleration divided by the square of the circular frequency. With a period of 0.5 s the circular frequency is 12.57 rad/s, so 3.924 divided by 158 gives about 0.0249 m, or 24.9 mm.
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