Machine-translated by Google. Questions are authored in English.
Top

Discussion

Let \(f : \mathbb{R} \to \mathbb{R}\) be a twice continuously differentiable function. The order of convergence of the secant method for finding root of the equation \(f(x) = 0\) is

  • A.\(\frac{1 + \sqrt{5}}{2}\)
  • B.\(\frac{2}{1 + \sqrt{5}}\)
  • C.\(\frac{1 + \sqrt{5}}{3}\)
  • D.\(\frac{3}{1 + \sqrt{5}}\)

Answer: A

The order of convergence is \(\frac{1 + \sqrt{5}}{2}\), about 1.618.

For the secant method near a simple root, the errors satisfy \(e_{n+1} \approx C e_{n} e_{n-1}\). Seeking \(|e_{n+1}| \approx A|e_{n}|^{p}\) and substituting gives \(p^{2} = p + 1\), whose positive root is the golden ratio:

\[ p = \frac{1 + \sqrt{5}}{2} \approx 1.618 \]

So the secant method is superlinear but slower than Newton's quadratic method. \(\frac{2}{1 + \sqrt{5}} \approx 0.618\) is the reciprocal, less than 1, which is not an order of convergence; \(\frac{1+\sqrt{5}}{3} \approx 1.08\) and \(\frac{3}{1+\sqrt{5}} \approx 0.93\) do not solve \(p^{2} = p + 1\).

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.