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If population size N is very large, then the approximate value of minimum sample size for estimating population mean with desired accuracy under SRSWOR design is :

where \(\alpha\) and d are \(P[|\overline{Y} - \overline{y}| \lt d] \ge 1 - \alpha\)

  • A.\(\left(\frac{s_{y} Z_{\alpha/2}}{d}\right)^{1/2}\)
  • B.\(\sqrt{N}\)
  • C.\(\frac{(s_{y} Z_{\alpha/2})^{2}}{d}\)
  • D.\(\left(\frac{s_{y} Z_{\alpha/2}}{d}\right)^{2}\)

Answer: D

The minimum sample size is approximately \(\left(\frac{s_{y} Z_{\alpha/2}}{d}\right)^{2}\).

Under SRSWOR, \(\mathrm{Var}(\overline{y}) = \left(\frac{1}{n} - \frac{1}{N}\right)s_{y}^{2}\). The accuracy condition \(P[|\overline{Y} - \overline{y}| \lt d] \ge 1 - \alpha\) requires \(Z_{\alpha/2}\sqrt{\mathrm{Var}(\overline{y})} \le d\):

\[ \begin{aligned} \frac{1}{n} - \frac{1}{N} &= \frac{d^{2}}{Z_{\alpha/2}^{2} s_{y}^{2}} \\ n_{0} &= \left(\frac{s_{y} Z_{\alpha/2}}{d}\right)^{2} \text{ when N is large} \end{aligned} \]

For finite N the correction is \(n = \frac{n_{0}}{1 + n_{0}/N}\).

The square root (option A) and dividing by d rather than \(d^{2}\) (option C) get the dimensions wrong, and \(\sqrt{N}\) has nothing to do with the accuracy required.

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