Discussion
A right cone of base radius 30 mm and height 40 mm is cut through its apex and across the base diameter. The triangular section has an area of
Answer: A
Correct answer: 1200 mm2
A cut through the apex and across the base diameter gives a triangle whose base is the full diameter and whose height is the height of the cone: \[ \frac{1}{2} \times 60 \times 40 = 1200\ \mathrm{mm^2}. \] Using the radius rather than the diameter as the base gives 600, which is the offered trap.
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