Discussion
1, 2, 3, 6, 9, 18, 34, ?
Answer: B
The numbers are alternately multiplied bt \(2\) and \(\frac{3}{2}\).
Thus \(1\times2=2,2\times \frac{3}{2}=3, 3\times 2=6,6\times \frac{3}{2}=9,..\)
\(\therefore\) Missing number = \(18 \times \frac{3}{2}=27\).
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