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If A and B are disjoint sets, then n(A ∩ B) is:

  • A.0
  • B.1
  • C.N(a)
  • D.N(b)

Answer: A

Disjoint sets share no elements at all, so their intersection is empty.

\[ n(A \cap B) = 0 \]

This is why \( n(A \cup B) = n(A) + n(B) \) for disjoint sets, with no correction term.

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