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If n(A) = 30 and n(B) = 40, and the two sets are disjoint, what is n(A Δ B)?

  • A.10
  • B.30
  • C.40
  • D.70

Answer: D

The symmetric difference A Δ B = (A ∪ B) - (A ∩ B).

Since the sets are disjoint, n(A ∩ B) = 0.

For disjoint sets, n(A ∪ B) = n(A) + n(B) = 30 + 40 = 70.

Therefore, n(A Δ B) = n(A ∪ B) - 0 = 70.

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