Discussion
A box of enclosed area \( 0.8 \) m\( ^2 \) must keep its shear flow below \( 150 \) kN/m. The largest torque it may carry is
Answer: A
Rearranging Bredt-Batho, \( T = 2Aq = 2 \times 0.8 \times 150 = 240 \) kN m. Note how directly the enclosed area buys torque capacity, which is why a deep, wide box is so much better in torsion than a slender one of the same material.
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