Discussion
A doubly symmetric box has walls of \( 3 \) mm and \( 1.5 \) mm thickness carrying the same shear flow. The ratio of shear stresses in them is
Answer: D
Correct answer: 1 to 2
Since the shear flow is the same in both walls, \[ \frac{\tau_3}{\tau_{1.5}} = \frac{q/3}{q/1.5} = \frac{1.5}{3} = \frac{1}{2}. \] The thin wall carries twice the stress of the thick one. This is the whole reason the thinnest wall of a torsion box governs its strength.
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