Discussion
A web \( 250 \) mm deep and \( 2 \) mm thick carries \( 50 \) kN of shear. Taking the flow as uniform, the shear stress is
Answer: A
Correct answer: 100 MPa
\[ \tau = \frac{V}{dt} = \frac{50{,}000}{250 \times 2} = 100\ \mathrm{MPa}. \] Taking the web to carry the shear uniformly over its full depth is the standard idealisation, justified when the flanges or booms carry the bending and the web carries the shear.
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