Discussion
A closed section requires \( 240 \) kN m of torque capacity at a shear flow limit of \( 200 \) kN/m. The minimum enclosed area is
Answer: D
Correct answer: 0.6 m^2
Rearranging the Bredt-Batho relation, \[ A = \frac{T}{2q} = \frac{240}{2 \times 200} = 0.6\ \mathrm{m}^2. \] Enclosed area is bought cheaply - it costs only the perimeter of skin needed to enclose it - which is why torsion boxes are made as deep and wide as the aerodynamic shape allows.
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