Discussion
A designer thins one face of a torsion box by half to save weight. The shear stress in that face
Answer: A
Correct answer: Doubles; the flow is unchanged
The shear flow depends on the torque and the enclosed area, neither of which the designer has changed, so \( q \) stays as it was and \( \tau = q/t \) doubles. Thinning one face of a torsion box therefore concentrates the penalty entirely on that face, and this is the standard way a weight saving turns into a strength problem.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development