Discussion
A beam, of 5 m effective span, has its left end 'P' as a free end; whereas its right end 'Q' is a fixed supported end. The beam is subjected to a uniformly distributed load of 3 kN/m on the entire span. Find the point with the maximum shear force.
Answer: A
The beam is a cantilever, free at P and fixed at Q, and loaded with a UDL of 3 kN/m. The shear force at a section a distance x from the free end is \(w x\), which grows steadily towards the fixed end and is greatest at the fixed support:
\[ V_{max} = wL = 3 \times 5 = 15\ \text{kN at Q} \]The shear at the free end P is zero, and at the midpoint it is 7.5 kN and at 1 m from the fixed support it is 12 kN, both smaller than the 15 kN at Q.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development