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A simply supported beam of span L is subjected to a couple Mo at a distance a from support A. Among the four options (Option-I to Option-IV) shown, the correct shear force diagram of the beam is

Beam AB with a counter-clockwise couple Mo at distance a from A, and four shear force diagrams: I a constant Mo/L (+); II +Mo/L before the couple and -Mo/L after; III triangles reaching Mo a/L and Mo(a/L-1); IV a triangle peaking at Mo/L

  • A.Option-I
  • B.Option-II
  • C.Option-III
  • D.Option-IV

Answer: A

The shear force diagram is Option-I, a constant \(M_{o}/L\) of positive sign.

A couple has no net vertical force, so the support reactions form an equal and opposite pair. Taking moments about B for the counter-clockwise couple gives \(R_{A} = M_{o}/L\) upward and \(R_{B} = M_{o}/L\) downward. These are the only vertical forces, and a concentrated couple changes the bending moment, not the shear force, so the shear is \(M_{o}/L\) along the whole span. With the sign convention shown (upward force on the left face positive) it is positive.

Option II shows a jump in shear at the couple, which only a concentrated force can cause. Options III and IV show sloping shear, which needs a distributed load, and none acts on the beam. The jump at the couple belongs in the bending moment diagram instead.

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