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An L-shaped rigid member is fixed at the midpoint of a simply-supported beam, as shown in figure (i). The member is subjected to a vertically downward force \(P\) at its free end. In an equivalent system, the member along with the applied load is replaced with a force \(Q = P\) and a moment \(M\) (see figure (ii)). Which of the following statements is correct?

(Neglect the mass of the beam and of the rigid member)

(i) Simply supported beam of span L with an L-shaped arm at mid-span rising height b and extending horizontally a, loaded by a downward force P at its tip; (ii) the same beam with a downward force Q and a moment M at mid-span

  • A.\(M = Pa\)
  • B.\(M = Pb\)
  • C.\(M = P(a + b)\)
  • D.\(M = 0\)

Answer: A

The equivalent moment is \(M = Pa\).

Moving a force to a new point without changing its effect requires adding a couple equal to the force times the perpendicular distance between the old and new lines of action. P is vertical and acts at a horizontal distance a from the vertical leg, which is fixed at mid-span, so moving it to the beam gives Q = P plus

\[ M = P \times a \]

The height b does not count, because it is measured along the line of action of the vertical force and contributes no moment arm. That rules out Pb and P(a + b), and M = 0 would hold only if P acted directly above the attachment point.

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