Machine-translated by Google. Questions are authored in English.
Top

Discussion

A simply-supported beam of rectangular cross-section (width \(w\) and height \(h\)) is subjected to the loads as shown in the figure (i). The enlarged view of the beam cross-section is shown in figure (ii). The coordinate system is indicated in the figures. Assuming Euler-Bernoulli beam approximation, the shear stress \(\tau_{xz}\) and normal stress \(\sigma_{xx}\) at the origin, O are respectively given by

(i) Simply supported beam of span L with equal downward loads P at L/4 from each support and the origin O at mid-span; (ii) the rectangular cross-section with O at its centre, at h/2 from the top and w/2 from the side

  • A.\(\frac{3P}{2wh}, \frac{3PL}{2wh^{2}}\)
  • B.\(0, \frac{3PL}{2wh^{2}}\)
  • C.\(\frac{3P}{2wh}, 0\)
  • D.0 , 0

Answer: D

Both stresses are zero: 0 , 0.

The origin O is at mid-span and at the centroid of the section. The loading is symmetric (equal loads P at a quarter span from each support), so each support carries P, and between the two loads the shear force is \(P - P = 0\). The shear stress \(\tau_{xz}\) at O is therefore zero.

The bending moment at mid-span is \(PL/4\), which is not zero, but O lies on the neutral axis, where the bending stress \(\sigma_{xx} = Mz/I\) vanishes because z = 0.

\(\frac{3P}{2wh}\) is the peak shear stress where the shear force is P, near the supports, and \(\frac{3PL}{2wh^{2}}\) is the outer-fibre bending stress at mid-span; neither occurs at O.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.