Discussion
The equivalent moment of inertia of the cross section in terms of timber of a flitched beam made up of steel and timber is (modular ratio, \(m = \frac{E_{s}}{E_{t}}\))
Answer: C
The equivalent moment of inertia is \(I_{t} + mI_{s}\).
In a flitched beam the steel plate is converted into an equivalent area of timber. Since steel is m times stiffer, with \(m = E_{s}/E_{t}\), the steel's width is multiplied by m, and so is its moment of inertia about the common neutral axis:
\[ I_{eq} = I_{t} + m I_{s} \]
Dividing by m (\(I_{s}/m\)) would be right only if the section were expressed in terms of steel. \(m/I_{s}\) has the wrong dimensions, and \(I_{t} + 2mI_{t}\) applies the modular ratio to the timber itself.
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development