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Number of flip-flops needed to construct a shift register capable of storing decimal numbers upto 32 are

  • A.6
  • B.4
  • C.5
  • D.2

Answer: A

Six flip-flops are needed, option (A). To store a decimal number up to 32 in binary, we have to be able to hold the value 32, which is 100000 and needs six bits. A shift register stores one bit per flip-flop, so six flip-flops are required. Five flip-flops, option (C), can hold the values from 0 to 31 only, because \(2^{5} = 32\) gives 32 combinations. Four, option (B), can hold up to 15, and two, option (D), only up to 3. The reading that the number 32 itself must be stored is what makes the answer six.

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