Discussion
A sinusoid of amplitude \( A \) has average power, in a one ohm load, of
Answer: D
The mean square of a sinusoid is half the square of its amplitude, so the power is \( A^{2}/2 \) and the root mean square value is \( A/\sqrt{2} \). \( A^{2} \) would be the peak instantaneous power. \( A/2 \) is a voltage rather than a power. \( A^{2}/4 \) results from squaring the mean rather than taking the mean of the square, an easy slip. The half factor propagates through every modulation power calculation in the subject, so it is worth holding firmly.
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