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A signal-to-noise ratio of 20 dB corresponds to a power ratio of

  • A.20
  • B.10
  • C.400
  • D.100

Answer: D

Inverting the power decibel relation:

\[ \mathrm{SNR} = 10^{20/10} = 100 \]

so the signal power is one hundred times the noise power. 20 is the decibel figure repeated as a ratio. 10 would correspond to 10 dB. 400 would follow from treating the 20 dB as a voltage ratio and then squaring, which double-counts the conversion. The 10 dB per decade of power is worth memorising in both directions, since link budgets are worked in decibels and thresholds are quoted as ratios.

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