Discussion
Raman paid Rs. 11400 as interest after 9 years. He had borrowed some money at rate of 6% for first two years, 9% for next three years and 14% for rest of the period. How much money did he borrow?
Answer: C
\[ \text{SI} = \frac{P \times R \times T}{100} \]
The rate changes with the period, so add the three slabs. Beyond five years leaves \( 9 - 5 = 4 \) years at 14%.
\[ P\left(\frac{6 \times 2}{100} + \frac{9 \times 3}{100} + \frac{14 \times 4}{100}\right) = 11400 \]
\[ P(0.12 + 0.27 + 0.56) = 0.95P = 11400 \]
\[ P = \text{Rs. } 12{,}000 \]
The final slab runs for four years, not nine - "beyond five years" means the remainder of the nine.
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