Discussion
Akhil borrowed a certain sum of money at the rate of 6%, 9% and 14% for a period of first two years, next three years and beyond the period of five years respectively. If at the end of nine years, he paid Rs. 8550 as interest, then find the sum of money he had borrowed.
Answer: A
\[ \text{SI} = \frac{P \times R \times T}{100} \]
Beyond five years leaves \( 9 - 5 = 4 \) years at 14%, so the three slabs are:
\[ P\left(\frac{6 \times 2 + 9 \times 3 + 14 \times 4}{100}\right) = 8550 \]
\[ P\left(\frac{12 + 27 + 56}{100}\right) = 0.95P = 8550 \]
\[ P = \text{Rs. } 9000 \]
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