Discussion

Simple interest at x% for x years will come out to be Rs x on a sum of Rs?

Answer: B

\[ \text{SI} = \frac{P \times R \times T}{100} \]

Both the rate and the time are \( x \), and the interest is also \( x \).

\[ x = \frac{P \times x \times x}{100} = \frac{P x^{2}}{100} \]

Dividing both sides by \( x \):

\[ 1 = \frac{Px}{100} \quad\Longrightarrow\quad P = \frac{100}{x} \]

Only one power of \( x \) survives the cancellation, which is what separates \( \tfrac{100}{x} \) from \( \tfrac{100}{x^{2}} \).

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