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Vijay lent out an amount Rs. 10000 into two parts, one at 8% p.a. and the remaining at 10% p.a. both on simple interest. At the end of the year he received Rs. 890 as total interest. What was the amount he lent out at 8% pa.a?

  • A.Rs. 6000
  • B.Rs. 5500
  • C.Rs. 4500
  • D.Rs. 5000

Answer: B

\[ \text{SI} = \frac{P \times R \times T}{100} \]

Let \( p \) be the part at 8%; the rest, \( 10000 - p \), earns 10%.

\[ 0.08p + 0.10(10000 - p) = 890 \]

\[ 0.08p + 1000 - 0.10p = 890 \quad\Longrightarrow\quad -0.02p = -110 \]

\[ p = \text{Rs. } 5500 \]

Checking: Rs. 440 from the 8% part and Rs. 450 from the Rs. 4500 at 10%.

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