Discussion
In how much time would the simple interest on a certain sum be 0.125 times the principal at 10% per annum?
Answer: A
\[ \text{SI} = \frac{P \times R \times T}{100} \]
\[ 0.125P = \frac{P \times 10 \times T}{100} = 0.1PT \]
\[ T = \frac{0.125}{0.1} = 1.25 = 1\tfrac{1}{4} \text{ years} \]
At 10% a year, interest of 12.5% of the sum takes a year and a quarter.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development