Discussion
A 4-pole, 50 Hz single phase induction runs with a forward slip of 0.1. Find the backward slip.
Answer: B
The backward slip is 1.9. For a single phase induction motor, the slip with respect to the backward rotating field is 2 minus the forward slip.
\[ s_b = 2 - s_f = 2 - 0.1 = 1.9 \]
The value 0.1 is the forward slip itself, 0.9 would be 1 minus the slip, and 2.1 would be 2 plus the slip. The backward field rotates in the opposite direction, so a rotor turning at 0.9 of synchronous speed forwards is seen by it as moving at 1.9 times the relative speed. So the second option is the answer.
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