Discussion
For a single-phase semi-converter, the input voltage is \(V_m \sin\omega t\). If the firing angle is \(90^\circ\), find the average DC output voltage.
Answer: B
For a single phase semi-converter (half controlled bridge) with a firing angle \(\alpha\), the average output voltage is
\[ V_{dc} = \frac{V_m}{\pi}(1 + \cos\alpha) \]
With \(\alpha = 90^\circ\), \(\cos\alpha = 0\), so
\[ V_{dc} = \frac{V_m}{\pi} \]
The value \(2V_m/\pi\) is the output at \(\alpha = 0\), where the bridge acts as an uncontrolled rectifier, and \(V_m/2\pi\) is the half wave controlled value at the same angle. The answer is option B.
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