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What does an unbypassed emitter resistor do to the gain expression?

  • A.It divides the gain by one plus the current gain of the device
  • B.It adds to the intrinsic emitter resistance in the denominator
  • C.It multiplies the gain by the ratio of the two resistors
  • D.It subtracts from the collector resistance in the numerator

Answer: B

The emitter resistance in the denominator becomes the external resistor plus the intrinsic 26-ohms-per-milliamp figure, and since the external one usually dominates the gain becomes a resistor ratio. That is what makes it predictable and temperature-independent. The gain falls rather than being multiplied, and beta does not enter. Adding a term to a denominator is the algebraic signature of series feedback wherever it appears. Working one numerical case through both schemes side by side fixes the distinction better than any rule of thumb. Working one numerical case through both schemes side by side fixes the distinction better than any rule of thumb.

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