Discussion
A stage has \( R_{C} = 4.7 \ \mathrm{k\Omega} \), \( I_{C} = 1 \ \mathrm{mA} \) and a bypassed emitter. Its gain is about
Answer: C
Dividing the load by the intrinsic emitter resistance:
\[ A_{v} = -\frac{4700}{26} \approx -180 \]
giving about -180. The figure depends on the operating current through that 26 ohms, so it moves with temperature and with any drift in the bias - which is exactly the unpredictability that degeneration is added to remove.
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