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How does leaving the emitter resistor unbypassed change the input impedance?

  • A.It becomes equal to the collector load divided by the gain
  • B.It rises, because the emitter resistance is now larger
  • C.It falls, because the resistor appears in parallel at the input
  • D.It is unchanged, since the resistor is outside the base circuit

Answer: B

The reflected quantity is now the external resistor plus the intrinsic one, so the input impedance rises by roughly the same factor as the gain falls. It appears in series with the emitter rather than in parallel with the input, and it is certainly inside the reflected path. That gain and input impedance move in opposite directions under series feedback is a general result, and it is often the reason degeneration is added in the first place. The parameter that varies and the parameter that does not are worth naming before any substitution is attempted. The parameter that varies and the parameter that does not are worth naming before any substitution is attempted.

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