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Why does a common-base stage have such a wide bandwidth?

  • A.Its input impedance is low enough to swamp the device's capacitances
  • B.Its current gain of just under unity limits the phase shift available
  • C.Its input and output are not bridged by a gain
  • D.Its collector-base capacitance is smaller than in other configurations

Answer: C

With the base common, the collector-base capacitance no longer bridges input and output across an inverting gain, so there is no Miller multiplication. The capacitance itself is the same device property in every configuration. The low input impedance helps but is not the mechanism, and the current gain is unrelated. Bandwidth is nearly always about which capacitance sees which gain, rather than about the size of the capacitance. Reading the definition literally, rather than recalling a formula, is the reliable route through questions of this shape. Reading the definition literally, rather than recalling a formula, is the reliable route through questions of this shape.

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