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By what factor does a base impedance appear smaller at the emitter?

  • A.The ratio of the two supply rails in the circuit
  • B.The square root of the current gain
  • C.One plus the current gain
  • D.The transconductance times the source resistance

Answer: C

Looking the other way the same rule inverts: a source impedance at the base appears at the emitter divided by one plus beta, which is why a follower's output impedance is so low. That the factor is the same in both directions, multiplying one way and dividing the other, makes the pair easy to hold once the reason is clear rather than the formula memorised.

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