Discussion
Match the List-I with List II and select the correct answer using the codes given below :
| List I | List II |
|---|---|
| (a) \(h_{fe}\) | (i) \(\left.\dfrac{\Delta v_{be}}{\Delta v_{ce}}\right|_{I_{B} = \text{constant}}\) |
| (b) \(h_{oe}\) | (ii) \(\left.\dfrac{\Delta v_{be}}{\Delta i_{b}}\right|_{V_{ce} = \text{constant}}\) |
| (c) \(h_{ie}\) | (iii) \(\left.\dfrac{\Delta i_{c}}{\Delta v_{ce}}\right|_{I_{b} = \text{constant}}\) |
| (d) \(h_{re}\) | (iv) \(\left.\dfrac{\Delta i_{c}}{\Delta i_{b}}\right|_{V_{ce} = \text{constant}}\) |
Answer: D
The correct matching is a-iv, b-iii, c-ii, d-i.
The CE hybrid parameters are defined with either the output voltage held constant (short-circuit parameters) or the input current held constant (open-circuit parameters):
- \(h_{fe} = \Delta i_{c}/\Delta i_{b}\) at constant \(V_{ce}\): forward current gain (iv).
- \(h_{oe} = \Delta i_{c}/\Delta v_{ce}\) at constant \(I_{b}\): output admittance (iii).
- \(h_{ie} = \Delta v_{be}/\Delta i_{b}\) at constant \(V_{ce}\): input impedance (ii).
- \(h_{re} = \Delta v_{be}/\Delta v_{ce}\) at constant \(I_{B}\): reverse voltage ratio (i).
The other codes swap the output admittance with the input impedance or the reverse ratio, which is easy to check from the units: only hoe is a current over a voltage.
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