Machine-translated by Google. Questions are authored in English.
Top

Discussion

A scientist attempts to replace a few carbon atoms in 1.0 g of diamond with boron atoms or nitrogen atoms in separate experiments. Which of the following is correct ?

  • A.The resulting material with B doping will be an n-type semiconductor
  • B.The resulting material with B doping will be a p-type semiconductor
  • C.B doping is not possible as B cannot form multiple bonds
  • D.The resulting material with N doping will be a p-type semiconductor

Answer: B

The correct statement is that with B doping the material will be a p-type semiconductor.

Each carbon in diamond forms four bonds. Boron has only three valence electrons, so a boron atom in a carbon site leaves one bond short of an electron, creating a hole. Holes are mobile positive charge carriers, so boron-doped diamond is a p-type semiconductor (natural blue diamonds owe their colour and conductivity to boron).

Nitrogen, with five valence electrons, donates an extra electron and gives n-type behaviour, so calling N-doped diamond p-type is wrong, as is calling B-doped diamond n-type. Substitutional doping does not require multiple bonds, so the statement that B cannot be incorporated is also false.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.