Discussion
A device dissipating 60 W through a total thermal resistance of 0.8 K/W from junction to ambient sits at a junction temperature of
Answer: C
Correct answer: 48 K above ambient
\[ \Delta T = P R_{th} = 60 \times 0.8 = 48\ \mathrm{K}. \] The thermal circuit is exactly analogous to an electrical one, with power as current and temperature difference as voltage. If the ambient is 40 degrees the junction sits at 88, which must be compared with the device limit of typically 125 or 150.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development