Machine-translated by Google. Questions are authored in English.
Top

Discussion

A three-phase diode bridge fed from a 415 V line supply gives a dc link voltage of about

  • A.560 V
  • B.415 V
  • C.587 V
  • D.240 V

Answer: A

The mean is \( 3V_{ml}/\pi = 3 \times 587/\pi = 560 \) V, and with a large capacitor it rises towards the peak of 587 V at light load. Drives are commonly specified with a link voltage of that order for a 415 V supply.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.