Discussion
If that device also drops 2 V while carrying 400 A for half the time, its conduction loss is
Answer: D
Correct answer: 400 W
Conduction loss is the on-state voltage times the current times the fraction of the time the device conducts: \[ 2 \times 400 \times 0.5 = 400\ \mathrm{W}. \] With the 160 W of switching loss the device dissipates 560 W in total, and it is that total which the thermal design must remove.
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