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What is the volume of methanol needed for making 2 L of 0.4 M solution? (Density of methanol = 0.64 kgL-1 and molar mass = 32 g mol-1)

  • A.20 mL
  • B.4 mL
  • C.40 mL
  • D.10 mL
  • E.80 mL

Answer: C

The volume needed is 40 mL.

Moles of methanol in 2 L of 0.4 M solution, then mass, then volume from the given density (0.64 kg L-1 = 0.64 g mL-1):

\[ \begin{aligned} n &= 0.4 \times 2 = 0.8\ \text{mol} \\ m &= 0.8 \times 32 = 25.6\ \text{g} \\ V &= \frac{25.6}{0.64} = 40\ \text{mL} \end{aligned} \]

20 mL and 80 mL halve or double the moles (using 1 L or 4 L), and 10 mL or 4 mL come from mixing up kilograms and grams in the density.

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