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The salt which has van't Hoff factor (i) as 1.82 in 0.001 m aqueous solution is

  • A.\(\mathrm{K_{2}SO_{4}}\)
  • B.\(\mathrm{MgSO_{4}}\)
  • C.KCl
  • D.NaCl
  • E.HCl

Answer: B

The salt is MgSO4.

MgSO4 gives two ions, so its ideal van't Hoff factor is 2. Interionic attraction between the doubly charged Mg2+ and SO42- ions is strong, so even at 0.001 m the observed factor is lower, 1.82 in the textbook table.

KCl and NaCl also give two ions, but their singly charged ions attract less, so their factor at 0.001 m is about 1.94. K2SO4 gives three ions, with a factor near 2.84. HCl, a strong acid, is close to 2 at this dilution.

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