Discussion
In a 9×20 cm fluted roller type seed drill, each fluted roller is discharging 4.25 g of seed per revolution of fluted roller shaft. The fluted roller shaft rotates once for two complete rotation of the ground drive wheel of the seed drill. The rolling diameter of the ground drive wheel is 0.35 m. Considering no skid of the ground drive wheel, the seed rate in kg ha-1 is
Consider π = 3.14
Answer: A
The seed rate is about 96.6 kg/ha.
A 9×20 drill has 9 furrow openers 20 cm apart, so it covers 1.8 m. The fluted shaft turns once for every two turns of the ground wheel:
\[ \begin{aligned} \text{distance per shaft turn} &= 2 \times 3.14 \times 0.35 = 2.198\ \text{m} \\ \text{area} &= 1.8 \times 2.198 = 3.956\ \text{m}^{2} \\ \text{seed} &= 9 \times 4.25 = 38.25\ \text{g} \end{aligned} \]
\[ \begin{aligned} \text{rate} &= \frac{38.25}{3.956} = 9.67\ \text{g/m}^{2} \\ &\approx 96.7\ \text{kg/ha} \end{aligned} \]
The paper prints this as 96.62, a small rounding difference. Forgetting the 2:1 drive ratio doubles the rate to about 193 kg/ha, which no option matches; 141.55, 187.35 and 386.42 are all well above the rate the drill actually sows.
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