Discussion
While sowing mustard seeds (bulk density = 800 kg.m-3), a four-row fluted roller type seed drill with 25 cm row spacing operates at a speed of 2.5 km.h-1. For a desired seed rate of 5.0 kg.ha-1, the flowrate of seeds from the machine in m3.h-1 is:
Answer: C
The flow rate is \(1.563 \times 10^{-3}\) m3.h-1.
Four rows at 25 cm spacing give a working width of 1 m. At 2.5 km/h the drill covers
\[ \begin{aligned} 1\ \text{m} \times 2500\ \text{m/h} &= 2500\ \text{m}^{2}/\text{h} = 0.25\ \text{ha/h} \\ \dot{m} &= 5.0 \times 0.25 = 1.25\ \text{kg/h} \\ Q &= \frac{1.25}{800} = 1.563 \times 10^{-3}\ \text{m}^{3}/\text{h} \end{aligned} \]
\(1.172 \times 10^{-3}\) is what three rows (0.75 m width) would give, \(0.391 \times 10^{-3}\) is the flow from a single row, and \(1.953 \times 10^{-3}\) would need a width of 1.25 m, that is five rows.
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